18x^2+36x+18=0

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Solution for 18x^2+36x+18=0 equation: 



18x^2+36x+18=0

a = 18; b = 36; c = +18;
Δ = b2-4ac
Δ = 362-4·18·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-36}{36}=-1$

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